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Oxygen Therapy Delivery Systems

Oxygen Therapy Delivery Systems

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Oxygen therapy is a critical intervention used whenever a patient's subjective and objective condition warrants it. While it is a life-saving treatment, clinicians must remember that "anoxia not only stops the machine, it wrecks the machinery". When administering oxygen, Respiratory Therapists (RTs) must select the appropriate device, assemble it correctly, and continuously monitor the patient's SpO2\mathrm{SpO}_{2}, cardiac status, and ventilatory status.

One of the most important distinctions in respiratory care is the difference between low-flow and high-flow systems. It is vital to note that "low flow" does not necessarily mean "low FiO2\mathrm{FiO}_{2}".

Low-Flow Oxygen Delivery Systems

Low-flow systems deliver an FiO2\mathrm{FiO}_{2} ranging from 0.22 to 0.80. In these systems, the RT sets a specific flow rate, but this rate is lower than the patient's actual inspiratory flow demand. Because the device cannot meet the patient's full demand, the patient draws in additional room air to supplement the oxygen. Consequently, the actual FiO2\mathrm{FiO}_{2} delivered is variable and is affected by the patient's breathing pattern, including tidal volume (VT\mathrm{V}_{T}), respiratory rate (RR), and inspiratory flow rate.

Nasal Cannula

The nasal cannula is a common low-flow device used to deliver oxygen through the nares.

  • Flow Rate: Typically 1–6 L/min in adults.
  • FiO2\mathrm{FiO}_{2} Range: Approximately 0.24 to 0.44.
  • Advantages: It is very comfortable, allowing patients to eat, talk, and perform hygiene without removal.
  • Disadvantages: It can cause significant nasopharyngeal mucosal irritation (drying) and skin irritation at pressure points like the ears.

Exam Tip: Estimating FiO2\mathrm{FiO}_{2} with a Nasal Cannula Assuming a normal RR and VT\mathrm{V}_{T}, each 1 L/min of oxygen increases the FiO2\mathrm{FiO}_{2} by approximately 4%.

Formula: Approximate FiO2=(Flow×4)+20\text{Approximate } \mathrm{FiO}_{2} = (\text{Flow} \times 4) + 20

Example: For a flow of 4 L/min: 4×4=164 \times 4 = 16 16+20=36% or 0.3616 + 20 = 36\% \text{ or } 0.36

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