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(PUCCAMP - SP) De forma simplificada, a reação da fotossíntese ficaria:6CO2+6H2O → C6H12O6 + 6O2Dadas as entalpias de formação do CO2 (- 94 kcal/mol), da H2O (- 58 kcal/mol) e da glicose (- 242 kcal/mol), pode-se concluir que o processo é:a) endotérmico e a energia envolvida, 392 kcal/mol de glicose.b) endotérmico e a energia envolvida, 1.152 kcal/mol de glicose.c) endotérmico e a energia envolvida, 670 kcal/mol de glicose.d) exotérmico e a energia envolvida, 1.152 kcal/mol de glicose.e) exotérmico e a energia envolvida, 670 kcal/mol de glicose

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