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同时记录max和min，然后可以这样避免负数 int min = nums[0], max = nums[0];int res = nums[0];for (int i = 1; i < nums.length; i++) {if (nums[i] >= 0) {max = Math.max(nums[i], max * nums[i]);min = Math.min(nums[i], min * nums[i]);} else if (nums[i] < 0) {int oldMax = max;max = Math.max(nums[i], min * nums[i]);min = Math.min(nums[i], oldMax * nums[i]);}res = Math.max(res, max);}return res;
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