Welcome to our exploration of systems of equations!A system of equations consists of multiple equations that share common variables.Here are two equations that form a system. Notice how they both contain x and y variables.Let's highlight how these equations share variables. First, notice how x appears in both equations.Similarly, y is also present in both equations.These equations can be visualized on a coordinate plane. Each equation represents a line.The first equation, x plus y equals 5, represents all points where the sum of x and y coordinates equals 5.The second equation, two x minus y equals 1, represents all points where twice the x coordinate minus the y coordinate equals 1.When we solve this system of equations, we're looking for the point that satisfies both equations simultaneously.In our next section, we'll explore how to find this solution graphically.To solve this system graphically, we'll plot both equations on the same coordinate plane.Let's start with the first equation: x plus y equals 5, shown in blue.Now we'll add the second equation: two x minus y equals 1, shown in red.These lines intersect at a single point. Let's zoom in to see exactly where.This intersection point occurs at x equals 2 and y equals 3. Let's verify this solution works in both equations.As we can see, the point (2,3) satisfies both equations, confirming it is the solution to our system.This graphical method gives us a visual way to understand how these equations work together to find a unique solution.Now let's explore algebraic methods for solving our system of equations.The substitution method involves solving for one variable in terms of the other.First, we solve equation one for y.Then substitute this expression into equation two.Simplify by distributing the negative.Combine like terms.Add five to both sides.Divide by three to solve for x.Now let's solve the same system using the elimination method.Let's apply these methods to a real-world problem.We can convert this word problem into a system of equations.Using substitution, we can solve for the prices.So we find that notebooks cost two dollars and pens cost four dollars.Let's verify our solution works in both equations.
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